The Bihar Technical Services Commission (BTSC) has announced a massive recruitment drive for 11,389 Staff Nurse vacancies in various government healthcare facilities across Bihar. This recruitment, officially notified on 25th April 2025, presents a golden opportunity for qualified nursing professionals to secure a prestigious government job. The online application process starts on 25th April 2025 and will continue until 23rd May 2025.

This recruitment aims to strengthen Bihar’s healthcare infrastructure by filling critical nursing positions in district hospitals, primary health centers, and other medical institutions. Selected candidates will play a vital role in patient care, medical assistance, and public health programs. The BTSC follows a transparent selection process, ensuring equal opportunities for all eligible candidates.

Applicants must meet the prescribed educational qualifications, age limits, and other eligibility criteria. The selection will be based on a written examination followed by document verification. Successful candidates will receive a competitive salary along with government benefits such as job security, pension, and allowances.

Interested candidates are advised to read the official notification carefully and apply online before the deadline. This recruitment drive is expected to attract a large number of applicants, so early preparation is recommended.

BTSC Staff Nurse Recruitment 2025 Key Overview:

• Organisation: Bihar Technical Services Commission (BTSC)
• Post Name: Staff Nurse
• Vacancies: 11,389 (Includes reservation categories)
• Apply Mode: Online Only
• Last Date: 23/05/2025
• Start Date: 23/04/2025
• Official Website: www.btsc.bihar.gov.in

BTSC Staff Nurse Recruitment 2025 Vacancy Details

Category	Vacancies
Unreserved	3134
EWS	784
SC	2853
ST	1097
Very Backward Class (VBC)	274
Backward Class (BC)	440
Backward Class Women (BCW)	121
Total	11389
Reserved for PwD (OH,HH,VH,MH)	156
Women Reservation (35%)	Included

Also see- TNPSC CCSE Group-IV 2025- 3935 Vacancy

BTSC Staff Nurse Recruitment 2025 Eligibility Criteria

Age Limit: 

• Minimum Age- 21 Years
• Maximum Age- 37 Years
• Age Relaxation as per norms.

Education Qualification: 

To apply for the BTSC Staff Nurse Recruitment 2025, the candidates must have –

• Passed General Nursing and Midwifery (GNM) from an institute recognized by the Indian Nursing Council (INC)
• Candidates from outside Bihar must get eligibility from INC, New Delhi.
• B.Sc. Nursing graduates are also eligible.
• Must be registered with the Bihar Nurses Registration Council, Patna.

Nationality: Indian

BTSC Staff Nurse Recruitment 2025 Application Fee

Category	Application Fee (Rs.)
UR/BC/EBC/EWS ( Bihar residents)	600
SC/ST/Female (Bihar residents)	150
All Categories from outside Bihar	150
PwD Candidates ( All Categories)	150

BTSC Staff Nurse Recruitment 2025 Selection Process

Written Exam (CBT)-75 Marks

• 100 Objective questions (MCQ)
• 2 hours duration
• Syllabus based on GNM Level
• 0.25 mark will be deducted per wrong answer

Work Experience- 25 Marks

• 5 marks per year ( up to max 25 marks)
• Valid only for contractual nurses working in Bihar government./ non-private hospital.

BTSC Staff Nurse Recruitment 2025 Salary & Posting

Pay Scale: 

• ₹9,300 – ₹34,800
• Grade Pay- Rs. 4600/-
• Pay Scale Level-07

Job Location: 

Bihar

BTSC Staff Nurse Recruitment 2025 Important Links

• Apply Online
• SSC Notification PDF

BTSC Staff Nurse Recruitment 2025 FAQs

1. What is the last date to apply for BTSC Staff Nurse 2025?

The last date for online application is 23rd May 2025.

2. How many vacancies are available?

A total of 11,389 Staff Nurse vacancies are open for recruitment.

3. What is the age limit for BTSC Staff Nurse?

The age limit is 21-37 years (with relaxations for reserved categories).

4. What is the selection process?

The selection will be based on a written exam followed by document verification.

5. What is the application fee for SC/ST candidates?

SC/ST candidates from Bihar need to pay ₹150/-, while General/OBC candidates pay ₹600/-.